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A cylindrical bucket (no cover), the bottom diameter is 40 cm, the height is 50 cm. To make two such buckets, at least how many square decimeters of iron sheet?
The diameter is 40 cm, the radius is 20 cm, the height is 50 cm, the radius is 2 mm
Bottom area = 2x2x3.14 = 12.56 square decimeters
Side area = 2x2x3.14x5 = 62.8m2
Iron sheet area = 62.8 + 12.56 = 75.36 square decimeters
A cylindrical tin bucket without a cover, 50 cm high and 20 cm in diameter at the bottom. How many square decimeters of tin do you need to make this bucket?
How much iron sheet is needed is the cylindrical surface area,
The radius is
20 / 2 = 10 cm
According to the bottom area + side area = surface area,
therefore
S=π×10²+π×20×50
=314+3140
=3454 square centimeters
=34.54 square decimeters
A cylindrical bucket without a cover has a diameter of 60 cm at the bottom and a height of 40 cm. How many square decimeters of iron sheet does it need to make such a bucket?
This problem is to find the area of a circle with a diameter of 60cm plus the area of a rectangle with a diameter of 60cm. The area of the circle is s = π (D / 2) ^ 2, the perimeter of the circle is C = π, and the area of the side is C = ch. suppose π = 3.14, how many square decimeters are needed? First, change the centimeter into decimeter to calculate s = s bottom + s
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