When n______ The equation (X-P) 2 + n = 0 has a solution______ ．

When n______ The equation (X-P) 2 + n = 0 has a solution______ ．

(X-P) 2 + n = 0, transfer the term to get: (X-P) 2 = - N, ∵ (X-P) 2 ≥ 0, ∵ - n ≥ 0, ∵ n ≤ 0, (X-P) 2 = - N, square both sides directly to get: X-P = ± n, then x = P ± − n, so the answer is: ≤ 0; X = P ± − n

When k is equal to what value, the equation x-3 branch x = 2 + x-3 branch K will produce increasing roots?

Is your original question X / x-3 = K / 2 + x-3? Then why not express it directly as X / x-3 = K / X-1? Confirm the question!

If a and B are fixed values, the equation 2kx + a3 = 2 + X − bk6 about X, no matter what the value of K is, its root is always 1. Find the value of a and B

Both sides of the equation are multiplied by 6 at the same time to get: 4kx + 2A = 12 + x-bk, (4k-1) x + 2A + bk-12 = 0 ①, ∵ no matter what the value of K is, its root is always 1, ∵ substitute x = 1 into ①, 4k-1 + 2A + bk-12 = 0, then when k = 0, k = 1, we can get the equations: − 1 + 2A − 12 = 04 − 1 + 2A + B − 12 = 0, the solution is a = 132, B = - 4