It is known that A1, A2, A3, A4 and A5 are five different integers satisfying the condition a1 + A2 + a3 + A4 + A5 = 9. If B is the integer root of the equation (x-a1) (x-a2) (x-a3) (x-a4) (x-a5) = 2009 about X, then the value of B is______ ．

Because (b-a1) (b-a2) (b-a3) (b-a4) (b-a5) = 2009, and A1, A2, A3, A4, A5 are five different integers, all b-a1, b-a2, b-a3, b-a4, b-a5 are also five different integers

It is known that A1, A2, A3, A4 and A5 are five different integers satisfying the condition a1 + A2 + a3 + A4 + A5 = 2. If B is the integer root of the equation (x-a1) (x-a2) (x-a3) (x-a4) (x-a5) = 2012 about X, then the value of B is
There has to be a process

First of all, there is prime factor decomposition 2012 = 2.2.503, that is, there are only three prime factors in 2012
Therefore, if 2012 is written as the product of five integers, at least two of them have no prime factor (i.e. ± 1)
If these five integers are different, then one is 1 and the other is - 1
The remaining three integers have exactly one prime factor, so they are 2, - 2 and 503
So 2012 is written as the product of five different integers in the way of 1 · (- 1) · 2 · (- 2) · 503
A1, A2, A3, A4 and A5 are different integers, and b-a1, b-a2, b-a3, b-a4 and b-a5 are five different integers
Their product is 2012, so it is an arrangement of 1, - 1,2, - 2503
Then 5B - (a1 + A2 + a3 + A4 + A5) = (b-a1) + (b-a2) + (b-a3) + (b-a4) + (b-a5) = 1 + (- 1) + 2 + (- 2) + 503 = 503
B = (503 + (a1 + A2 + a3 + A4 + A5)) / 5 = 101

Given that M is an integer and the point (12-4m, 13-3m) is in the second quadrant, the value of M & # 178; + 2005 is

Solution
The point is in the second quadrant
be
12-4m0
Namely
m>3
m

It is known that the image of positive scale function y = (2m-1) x ^ 3M ^ 2-2 passes through the second and fourth quadrants
(1) Finding the value of M
(2) If a (3, a), B (radical 5, b) are two points on the image, find a, B

(1) From the meaning of the title, we can get 3M & # 178; - 2 = 1, and 2m-1

Given that the point P (3m-2, M + 1) is in the second quadrant, then the value range of M is?

Because point P (3m - 2, M + 1) is in the second quadrant
So 3M - 2 < 0 and M + 1 > 0
So - 1 < m < 2 / 3

Given that M is a positive integer, 3M power of a = 6, find the value of 6m + 5 of A

6m + 5 of a = (a ^ (3m)) &# 178; + 5 = 6 & # 178; + 5 = 41

M is a natural number and 3m / M-1 is an integer

M and M-1 coprime
So 3m / (m-1) is an integer
M-1 must be divisible by 3
And because m is a natural number
So M-1 = 1 or 3
M = 2 or 4

When x is an integer, is the value of fraction 6x ^ 2-12x + 6 / (1-3) ^ 3 an integer?

Simplify (3x ^ 2-6x + 3) / 4 3 (x ^ 2-2x + 1) * 3 / 4 x ^ 2-2x + 1 must be a multiple of 4, that is, (x-1) ^ 2 X-1 is even and X is odd

If ax + 2Y + 6 = 0 and X + a (a + 1) y + (A2-1) = 0 are perpendicular, then the value of a is ()
A. - 32 or 0b. 0C. - 23 or 0d. - 3

The straight line ax + 2Y + 6 = 0 and the straight line x + a (a + 1) y + (A2-1) = 0 are perpendicular, which is obviously true when a = 0; when a ≠ 0, there is − A2 (− 1a (a + 1)) & nbsp; = − 1 solution, which leads to a = - 32, so we choose a

If the line ax + 2Y + 6 = 0 is perpendicular to the line x + a (a + 1) y + (a ^ 2-1) = O, then the value of a is?

A=-3/2
The vertical slope of two lines is multiplied by - 1
(-a/2)*(-1/(a(a+1)))=-1
The result is a = - 3 / 2
I don't know if I miscalculated. That's what I did. You'd better do it yourself

It is known that A1, A2, A3, A4 and A5 are five different integers satisfying the condition a1 + A2 + a3 + A4 + A5 = 9. If B is the integer root of the equation (x-a1) (x-a2) (x-a3) (x-a4) (x-a5) = 2009 about X, then the value of B is______ ．