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If the lines ax-y + 8 = 0 and x-2y + 1 = 0 are perpendicular to each other, what is the value of the real number a Help! Urgent ~
-2. Vertically, the slope product is - 1
If the line ax + 2Y + 1 = 0 is perpendicular to the line x + Y-2 = 0, then a=______ ．
The line ax + 2Y + 1 = 0 and the line x + Y-2 = 0 are perpendicular to each other. Because of the existence of the slope of the line, the slope product is - 1, that is - 1 · (− A2) = - 1, so a = - 2. So the answer is: - 2
x-1=3x+3 x-3=12-4x 6x-14=5x-10 x+1=2-4x
Quick solution of equation
X-1=3X+3
2X=-4;X=-2
x-3=12-4x
5X=15；x=3
6x-14=5x-10
x+1=2-4x
5x=1;x=0.2
1x2−3x+2+1x2−5x+6+1x2−4x+3．
The original formula = 1 (x − 2) (x − 1) + 1 (x − 2) (x − 3) + 1 (x − 1) (x − 3) = x − 3 + X − 1 + X − 2 (x − 1) (x − 2) (x − 3) = x − 3 + X − 1 + X − 2 (x − 1) (x − 2) (x − 3) = 3 (x − 2) (x − 1) (x − 2) (x − 3) = 3 (x − 1) (x − 3)
5X+2/3＞3X+9
5x + 2 / 3 ＞ 3x + 9
5X+2/3＞3X+9
The coefficient of 2x > 25 / 3 is 1
x>25/6
The solution of the inequality is
x>25/6
Using equation to solve 5x-3 * 2 = 3x = 9
5x-6＝9
3x＝9
x＝3
It is known that if the values of 5x-8 and 3x + 7 are opposite to each other, what is x = then
One eighth
Given that 5x-8 and 3x + 7 are opposite numbers, then x=
Because 5x-8 and 3x + 7 are opposite numbers
So 5x-8 + 3x + 7 = 0
8x-1=0
x=1/8
Given that x2-5-1999 = 0, find the value of the algebraic formula (X-2) &# 179; - (x-1) &# 178; + 1 divided by X-2
X2-5-1999 = 0 should be changed to x2-5x-1999 = 0
((x-2)³-(x-1)²＋1)/(x-2)=(x-2)^2-((x-1)^2-1)/(x-2)=(x-2)^2-x(x-2)/(x-2)=x^2-4x+4-x=x^2-5x+4
∵x^2-5x-1999=0
∴x^2-5x=1999
∴((x-2)³-(x-1)²＋1)/(x-2)=1999+4=2003.
When x is one of the four numbers 0,1, - 1, - 2, the value of the algebraic formula - X - | x | divided by X & # 178; + X is 0?
According to - X - | x | = 0 ① (molecule is zero) x & # 178; + X ≠ 0 ② (denominator is not zero)
From (1) we get | x | = - x = > x ≤ 0
From ②, we get x (x + 1) ≠ 0 = > x ≠ 0 and X ≠ - 1
To sum up, x = - 2
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