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X cube + 4x square y + 4xy square
x(x^2-4xy+4y^2)
=x(x-2y)^2
(X-Y) cube + 4x square y-4xy square
=(x-y)^3+4xy(x-y)
=(x-y)[(x-y)^2+4xy]
=(x-y)(x+y)^2
{x+y=5{3x-7y=11
①x+y=5
②3x-7y=11
The results show that ① × 7 is: ③ 7x + 7Y = 35
Using the formula of 2 + 3, we can get: 4 3x-7y + 7x + 7Y = 11 + 35, i.e. 10x = 46, i.e. x = 4.6
Substituting into ①, y = 5-x = 0.4
3x (x-1) = 2-2x 3x (x-1) - 2 (1-x) = 0 (x-1) (3x + 2) in this step, I don't know how he came out. Who can teach me?
3x(x-1)=2-2x
3x（x-1）-2（1-x）=0
(x-1) (3x + 2) in this step, I don't know how he came out. Who can teach me?
3x(x-1)=2-2x
3x(x-1)-(2-2x)=0
3x(x-1)-2(1-x)=0
3x(x-1)+2(x-1)=0
(x-1)(3x+2)=0
I know the solution of 3 (x + 2) = 4 (x + 1). I don't know the meaning of "term shifting"?
First, open the brackets: 3x + 6 = 4x + 4
Then move the one with X to one side, but don't forget to change the sign when you move to the other side of the equal sign,
So move 4 to the left and make 6-4
Then move 3x to the right and make 4x-3x
So: 6-4 = 4x-3x
2=x
x=2
See?
Let - x △ (2x + 1) denote the composition formula. I know that the value range of X in the formula is
Let - x (2x + 1) denote the composition formula as this, I know, the value range of X in the formula is, please help me quickly, if you are bored
The denominator 2x + 1 is not equal to 0
So x is not equal to - 1 / 2
1 / 2 (1-2 / 3x (x-3 / 1)) = 1 / x-3
1/2[1-3/2x(x-1/3)]=x-1/3
1/2(1-3/2x²+1/2x)=x-1/3
6-9x²+3x=12x-4
9x²+9x-10=0
(3x-2)(3x+5)=0
x=2/3 x=-5/3
x\2=y\3=z\4 3x+y+2z=51
Solving equations
x\2=y\3=z\4
Let x = 2T, y = 3T, z = 4T
Substituting 3x + y + 2Z = 51
Then 6T + 3T + 8t = 51
∴ 17t=51
∴ t=3
∴ x=6,y=9,z=12
X + 40% x = 21, X-15% x = 51, 3 / 4 X-2 x = 1 / 9
x=15,x=60,x=4/9
4. Solve the following equations: ①, 1 / 3x + 1 / 2Y = 7, 2 / 3x-y = 1, ②, 2 (x + 1) = 3 (Y-2), 3 (y + 1) = x + 5
① 1 / 3x + 1 / 2Y = 7,2 / 3x-y = 12x + 3Y = 422x-3y = 3, 4x = 45x = 45 / 4, then y = 13 / 2, ②, 2 (x + 1) = 3 (Y-2), 3 (y + 1) = x + 52X + 2 = 3y-62x-3y = - 8, ① 3Y + 3 = x + 5x-3y = - 2, ② - ②, x = - 6, then substitute ①, then - 12-3y = - 83y = - 4Y = - 4 / 3
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