X - three fifths x = eight ninths. How about x

X - three fifths x = eight ninths. How about x

X - three fifths x = eight ninths
（1-3/5）X=8/9
2/5X=8/9
X=8/9*5/2
X=20/9
twenty-ninths

How about 4 / 9-3 / 8 + 5 / 9

4 / 9-3 / 8 + 5 / 9
=4 / 9 + 5 / 9-3 / 8
=1-3 / 8
=5 out of 8

A3 + 1 factorization is more detailed

a³＋1
The original formula = A & # 179; + 1 & # 179;
＝﹙a＋1﹚﹙a²－a＋1﹚

Factorization: (1) a4-a3 + a2-a (2) 4a2-9b2 + c2-4ac

：（1）a4－a3＋a2－a
=a³(a－1)＋a(a－1)
=(a³＋a)(a－1)
=a(a²＋1)(a－1)
（2）4a2－9b2＋c2－4ac
=4a²－4ac＋c²－9b²
=(2a－c)²－(3b)²
=(2a＋3b－c)(2a－3b－c)

Factorization of A3 + 1
Factorization A3 (power) + 1

a^3+1=(a+1)(a^2-a+1)

What is the factorization of A3 + a2-a-1?

(a + 1) ^ 2 * (A-1) the first and third items are combined, the second and fourth items are combined, and then the common factor is extracted

Factorization of a3-3a2-3a-5 / 8

a³ - 3a² - 3a -5/8 = 0
8a³ - 24a² -24a - 5 = 0
(2a +1)(4a² -14a -5) = 0

A0 + A1 (x + 1) + A2 (x + 1) 2 + A3 (x + 1) 3 + A4 (x + 1) 4 + A5 (x + 1) 5 = (x + 2) 5 + (x-1) 3 is true for any x belonging to R. find the value of A2 + A4

Let x = 0
a0+a1+a2+a3+a4+a5=2^5-1=31 ..(1)
Let x = - 1
a0=1-8=-7 ..(2)
Let x = - 2
a0-a1+a2-a3+a4-a5=-27 ..(3)
(3) + (1) - 2 × (2)
2a2+2a4=18
a2+a4=9
If the explanation is not clear enough,

(x-1) 5 = A0 + A1 (x + 1) A2 (x + 1) 2 + A3 (x + 1) 3 + A4 (x + 1) 4 + A5 (x + 1) 5 find A3, feel can't calculate ah, can only calculate A2 + A4, as if the answer is 30 or 20 don't remember,

Let t = x + 1, then: (T-2) ^ 5 = A0 + A1 · T + A2 · T ^ 2 + a3 · T ^ 3 + A4 · T ^ 4 + A5 · T ^ 5 ■ & nbsp; A3 = C (5,3) · (- 2) ^ 3 = - 80

Given that a1 + A2 + a3 + A4 + A5 = 9, B is the integer root of the equation (x-a1) (x-a2) (x-a3) (x-a4) (x-a5) = 2009 about X, find the value of B
Urgent, with junior high school method to answer

I just saw that I didn't bring a pen. I think I can figure it out with a pen. I suggest you look for a book to see the following examples