In x-3y, the coefficient of the term containing y is

In x-3y, the coefficient of the term containing y is


1. If the title is x / 2-3y, then the coefficient of the term containing y is - 3
2. If the title is (x-3y) / 2, then the coefficient of the term containing y is - 3 / 2



In the algebraic formula - (x-3y / 3), the coefficient of the term containing y is ()


1
-1/3x +y
Do not understand, welcome to ask
Thank you very much!



In the bivariate linear equation 2x-1 / 5 + 3y-2 / 4 = 2, if y is expressed by an algebraic expression containing x, then y = (); if x is expressed by an algebraic expression containing y, then x = ()
The problem is not to solve the equation, but to use the algebraic expression containing x to express y, then y = (); use the algebraic expression containing y to express x, then x = (is a blank filling problem


y=-(2/3)x+27/30 x=-(3/2)y+27/20



Given the equation 5x + 3Y = 2, it is written as an algebraic expression with X, and the form of Y is______ .


5x + 3Y = 2, 3Y = - 5x + 2, y = - 53 + 23



3x^2+7x-10


If it is factorization, please see the following solution:
3x^2+7x-10
=(3x+10)(x-1)
If you want to solve the equation, please see the following solution:
3x^2+7x-10=0
(3x+10)(x-1)=0
X = - 10 / 3 or x = 1



3x square - 2x-6 = 0
2 X(X-1)=3X+7
3. The ratio of length to width of rectangle is 5:2, the height is 5cm, and the surface area is 40


(1)
3x²-2x-6=0
a=3 b=-2 c=-6
Substituting into the root formula
x=[2±√(4+72)]/6=(1±√19)/3
therefore
x1=(1±+√19)/3 x2=(1-√19)/3
(2)
X(X-1)=3X+7
x²-x-3x-7=0
x²-4x-7=0
a=1 b=-4 c=-7
Substituting into the root formula
x=[4±√(16+28)]/2=2±√11
therefore
x1=2+√11 x2=2-√11
(3) If the length is 5x, the width is 2x
(5x×2x+5x×5+2x×5)×2=40
(10x²+35x)×2=40
10x²+35x=20
2x²+7x-4=0
(x+4)(2x-1)=0
X + 4 = 0 or 2x-1 = 0
X = - 4 (rounding off) x = 0.5
So the length is 5x = 2.5 (CM) and the width is 2x = 1 (CM)



How to find the square of 3x - 10x + 6 = 0


3x^2-10x+6=0,
——》x=[10+-v(100-4*3*6)]/2*3=(5+-v7)/3.



Given the square of X + 3x-6 = 0


From X & sup2; + 3x-6 = 0,
From the root formula:
x=(-3±√(3²+4×6)/2
=(-3±√33)/2.



How to find 3x + 5 = 7x-3


3x+5=7x-3
3x-7x=-3-5
-4x=-8
x=-8÷(-4)
x=2



2.3x+7.7x-5=2.8 x=


Solution 10x = 2.8 + 5
10x=7.8
x=0.78