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What's the total number of 0-9 permutations in a group of four, the most complete answer, thank you!
P9 (4) - P (83) = 9 * 8 * 7 * 6-8 * 7 * 6 = 8 * 8 * 7 * 6, in which the subtracted is the permutation number of 4 out of 9, and the subtracted is the permutation number of 3 out of 8
It's too hard for me to write completely
0-9 7 digit permutation
Do you want all of them
Is arranged as: 1234567
You're talking about numbers that can't be repeated
The highest position cannot be 0
So it's 9 x 9p6 = 9 x 9 x 8 x 7 x 6 x 5 x 4
= 544320
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- 1. Take any 4 digits from 0 to 9 to form a 5-digit permutation The number permutation and combination problem of 0-9 Any four of the ten digits from 0 to 9 make up five digits. 0 can be placed in the first place. The first three digits must not be the same, and the last two digits can repeat at most one digit with the first three digits. How many digits are there, Any four of the ten digits 0-9 make up five digits. 0 can be put in the first place. The first three digits can't be the same. The last two digits can repeat only one digit and the last two digits can be the same. How many permutations are there
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