Take any 4 digits from 0 to 9 to form a 5-digit permutation The number permutation and combination problem of 0-9 Any four of the ten digits from 0 to 9 make up five digits. 0 can be placed in the first place. The first three digits must not be the same, and the last two digits can repeat at most one digit with the first three digits. How many digits are there, Any four of the ten digits 0-9 make up five digits. 0 can be put in the first place. The first three digits can't be the same. The last two digits can repeat only one digit and the last two digits can be the same. How many permutations are there

Take any 4 digits from 0 to 9 to form a 5-digit permutation The number permutation and combination problem of 0-9 Any four of the ten digits from 0 to 9 make up five digits. 0 can be placed in the first place. The first three digits must not be the same, and the last two digits can repeat at most one digit with the first three digits. How many digits are there, Any four of the ten digits 0-9 make up five digits. 0 can be put in the first place. The first three digits can't be the same. The last two digits can repeat only one digit and the last two digits can be the same. How many permutations are there

In the first case, the five numbers are different, a (10,5)
Under the second modification, the first three digits are a (10,3). If the last two digits are the same as the previous ones, they may be in 3 * 2 * 7. If they are different, there may be seven kinds of numbers for each digit
So the second case should have a (10,3) * (3 * 2 * 7 + 7 * 7) =?
It doesn't matter

What are the numbers of 0000-9999 four digit permutation

There are 10000 numbers from 0 to 9999, 0 is 0000, 1 is 0001, 2 is 0002