As shown in the figure, point C is the point on line AB, and points D and E are the midpoint of line AC and BC respectively. If AC = 3cm and BC = 2cm, what is de? —·———·————·———————·————————·———— A D C E B

As shown in the figure, point C is the point on line AB, and points D and E are the midpoint of line AC and BC respectively. If AC = 3cm and BC = 2cm, what is de? —·———·————·———————·————————·———— A D C E B

As shown in the figure, point C is the point on line AB, and points D and E are the midpoint of line AC and BC respectively. If AC = 3cm and BC = 2cm, what is de?
AC = 3, D is the midpoint of AC, so ad = DC = 1.5
BC = 2, e is the midpoint of BC, so CE = EB = 1
De = DC + CE = 1.5 + 1 = 2.5cm

As shown in the figure, D is the midpoint of AB, e is the midpoint of BC, be = 15ac = 2cm, find the length of de

Because be = 15ac = 2cm, so AC = 5be = 10cm. Because e is the midpoint of BC, so BC = 2be = 2 × 2 = 4cm. So AB = ac-bc = 10-4 = 6cm. And D is the midpoint of AB, so DB = 12ab = 12 × 6 = 3cm. So de = DB + be = 2 + 3 = 5cm

As shown in the figure, it is known that C is any point of line AB and M is the midpoint of line BC. Let's explain that am = 1 / 2 (AB + AC)

Let AB be 1
Let AC = X
Then BC = 1-x
AB+AC=1+X
CM=1/2BC=1/2(1-X)
AM=AC+CM=1/2+1/2X=1/2(1+X)=1/2(AB+AC)