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Line AB = 40mm, draw line BC = 16mm on line AB, D is the midpoint of AC, and find the length of CD
Point C is on line ab
ac=40-16=24mm
cd=1/2ac=12mm
or
Point C is outside the line ab
ac=40+16=56mm
cd=1/2ac=28mm
Given the line segment AB = 50mm, draw the line segment BC = 20mm on the line AB, and point D is the midpoint of AC to find the length of CD
AB=50,BC=20
AC=50-20=30
D is the midpoint of AC, so ad = CD = 1 / 2Ac = 0.5 * 30 = 15
It's very easy to draw···
A______ D______ C________ B
15 15 20
fifty
In short, that's it···
Given that the length of line AB is 40, draw line BC = 16 on line AB, point D is the midpoint of line AC, and calculate the length of line CD,
In two cases, if BC is on the extension line of ray AB, then it has (40 + 16) △ 2 = 28; if BC is on the line AB, then it has (40-16) △ 2 = 12
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