As shown in the figure, ab ⊥ BC, BC ⊥ CD, BF and CE are rays, and ∠ 1 = 2, try to explain BF ⊥ CE

As shown in the figure, ab ⊥ BC, BC ⊥ CD, BF and CE are rays, and ∠ 1 = 2, try to explain BF ⊥ CE


It is proved that: ∵ ab ⊥ BC (known), ∵ ABC = 90 ° (vertical definition); ∵ BC ⊥ CD (known), ∵ BCD = 90 ° (vertical definition), ∵ ABC = ∵ DCB; ∵ 1 = ∵ 2 (known), ∵ ABC - ∵ 2 =