It is known that the coordinates of three vertices of square ABCD are a (2,3) B (6,6) C (3,10), and the coordinates of point D can be obtained

Obviously, the four vertices of the square ABCD are all on the circumference of the same circle,
The center point O (2.5,6.5) of AC is the center of the circle,
Similarly, the distance from point B and point d to o is equal, that is, O is the midpoint of BD
Let the coordinates of d be (x, y)
So (x + 6) / 2 = 2.5, (y + 6) / 2 = 6.5
The solution is x = - 1, y = 7
The coordinate of point D is (- 1,7)

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