The cross section of the reservoir dam is trapezoidal, the width of the dam crest is 5m, the slope ad = 6 √ 2m, the dam height is 6m, and the slope of the oblique wave bc i = 1: √ 3, Calculate the low width ab of the dam and the slope angle ∠ a of the slope ad

The cross section of the reservoir dam is trapezoidal, the width of the dam crest is 5m, the slope ad = 6 √ 2m, the dam height is 6m, and the slope of the oblique wave bc i = 1: √ 3, Calculate the low width ab of the dam and the slope angle ∠ a of the slope ad


The slope of oblique wave bc i = 1: √ 3, so CF / BF = tanb = 1: √ 3, BF is the height of dam 6 meters, so BF = 6 √ 3 meters, De is also the height of dam 6 meters, and De is perpendicular to AB, slope ad = 6 √ 2 meters, in right triangle ade, ad is the hypotenuse, so ad & # 178; = ae



The cross section of a seawall is trapezoidal, the upper and bottom ad is 4m, the slope of the upstream surface (slope AB) is I1 = 1: root 3, and the length of slope AB is 12m,
The slope of backwater slope (slope CD) is I2 = 1:1, and the slope angle of (1) slope AB, (2) the width of embankment bottom BC and the length of slope CD are calculated


(1) If the length of slope AB is 12 m, the slope angle of slope AB is 30 ° and the opposite side of slope AB is half of the slope. If the height of dike top is 6 m, the slope length is 6 * (root 3) = 10.39 m, the backwater slope (inclined slope) is 6 m



As shown in the figure, the cross section of a reservoir dam is an isosceles trapezoid with a crest width of 6 meters and a dam height of 10 meters. The slope of slope AB is 1:2 (AR: BR). Now, if the crest width and slope gradient are unchanged, how much earthwork is needed to reinforce a 50 meter long dam


∵ in RT △ ABR, the slope of slope AB is 1:2, ar = 10, ∵ br = 20m, and∵ trapezoid ABCD is isosceles trapezoid, then BC = 2Br + ad = 46m, ∵ s trapezoid ABCD = (AD + BC) × ar △ 2 = 260m2, ∵ the slope of AB has no change before and after the transformation, and eh ⊥ BC is made at point h through point E