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Given | 2a-1 | + | 3b-2 | = 0, find the value of a + B fast
because
|2a-1|>=0
|3b-2|>=0
therefore
|2a-1|=0
|3b-2|=0
2a-1=0
3b-2=0
a=1/2
b=2/3
a+b=1/2+2/3=7/6
Given that the square of | a + 3 | + (b-2) is 0, (1) find the value of 2a-3b, (2) find the 100th power of (a + b)
Given that the square of | a + 3 | + (b-2) is 0, (1) find the value of 2a-3b, (2) find the 100th power of (a + b)
therefore
a+3=0,b-2=0
a=-3,b=2
therefore
（1）2a-3b=-6-6=-12
(2) The hundredth power of (a + b) = the hundredth power of (- 1) = 1
Given (2a + 3B + 100) ^ 2 + (3a-b-1) ^ 2 = 0, find the value of a ^ 2 + 2Ab + B ^ 2
Such as the title
Well, I'm really sorry. I've got the wrong number in the title.. (2a + 3B + 1) ^ 2 + (3a-b-1) ^ 2 = 0. I'm sorry if I can get the value of a ^ 2 + 2Ab + B ^ 2 again
It can be seen from the question that 2A + 3B + 1 = 0 and 3a-b-1 = 0
The solution is a = 2 / 11, B = - 5 / 11
So a ^ 2 + 2Ab + B ^ 2 = (a + b) ^ 2 = (- 3 / 11) ^ 2 = 9 / 121
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