Given 10 ^ a = 2, 10 ^ B = 3, find 100 ^ 2a-1 / 3B

Given 10 ^ a = 2, 10 ^ B = 3, find 100 ^ 2a-1 / 3B


It should be 100 ^ (2a-b / 3)
100^(2a-b/3)
=100^2a÷100^(b/3)
=(10^a)^4÷(10^b)^(2/3)
=16÷3^(2/3)
=16×{[3^(1/3)]/3}
=16 / 3 times the root 3