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應該是求100^(2a-b/3)吧 100^(2a-b/3) =100^2a÷100^(b/3) =(10^a)^4÷(10^b)^(2/3) =16÷3^(2/3) =16×{[3^(1/3)]/3} =3分之16倍的3次根號3
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