Seventh grade mathematics problem: if the absolute value of A-3 is known to be A-3, then A-3 = 0, and the value range of a is greater than or equal to 3. If the opposite number of A-3 - 3A + a = 0, find the value of A

Seventh grade mathematics problem: if the absolute value of A-3 is known to be A-3, then A-3 = 0, and the value range of a is greater than or equal to 3. If the opposite number of A-3 - 3A + a = 0, find the value of A

The question may be | A-3 | = A-3, then A-3 ≥ 0, a ≥ 3; if the opposite number of A-3 | 3-A | = A-3, find the value range of A
According to the property of absolute value, if x

The absolute value of 3-radical 10 is equal to?

Root 10 - 3

If a and B are opposite to each other and C and D are reciprocal to each other, the calculation process of a + B power of 2010 plus 2010 power of negative CD is obtained

2011^(a+b)+(-cd)^2010
=2011^0+(-1)^2010
=1+1
=2

If m square + Mn = 2 - Mn-N square = 1, then the value of m square + 2Mn + n square is?

m²+mn=2 -mn-n²=1,
Then M & # 178; + 2Mn + n & # 178; = 2

If the square of M-N + 1 + (nm + 2) in the absolute value is known to be 0, then the value of the bisection n of the square of mn-m is 0
If the square of M-N + 1 + (nm + 2) in the absolute value is known to be 0, then the square of Mn - the square of m n is 0

There are M-N + 1 = 0 and Mn + 2 = 0

Define the new operation m [n = Mn + m + N, then fill several pairs of brackets in 1 [?
If you answer right, you will take it (first place)
It's a process
O(∩_ Thank you

(m☆n)☆p = (mn + m + n)☆p = (mnp + mp + np) + (mn + m + n) + p
m☆(n☆p) = m☆(np + n + p) = (mnp + mn + mp) + m + (np + n + p)
So this operation is in accordance with the law of association: (m ￣ n) ￣ P = m ￣ (n ￣ P)
So no matter how to add brackets, the result is the same, there is only one calculation result

A new operation "*" is defined. It is known that 1 / m * n = 1 / M + 1 / N, for example, m * n = 6, (1 / M) * (1 / N) = 25, Mn =?

M * n = 1 / (1 / M + 1 / N) = Mn / (M + n) = 6, Mn = 6 (M + n)
1 / m * 1 / N = 1 / (M + n) = 25, then M + n = 1 / 25. To sum up, Mn = 6 / 25

Any two positive integers, define some kind of operation *, m * n = ① m + n (M and N are the same parity) ② Mn (M and N are different parity)
Then the set M = {(a, b) a * b = 36, a, B belong to N +}
The number of elements in is, the answer is 41,

The discussion is divided into two situations
① M, n with odd or even: for (1,35), (2,34), (3 + 33), (35,1), (35,1), a total of 35 groups
② M, n odd and even: first factor 36, 36 = 2 × 2 × 3 × 3
There are six groups of heterozygosity: (1,36), (4,9), (12,3), (36,1), (9,4), (36,1)
So the answer is: 35 + 6 = 41~

New operations are defined: m # n = mn-5 (M + n), (1) if 6 # y = 9, find the value of Y; (2) if 7 # (x # 7) = 7, find the value of X

(1) 6#y=9,
That is 6y-5 (6 + y) = 9
6y-30-5y=9
The solution is y = 39
(2)∵x#7=7x-5(x+7)=2x-35
∴7#(x#7)=7#(2x-35)=7
That is, 7 (2x-35) - 5 (7 + 2x-35) = 7
It is reduced to 4x = 112,
The solution is x = 28

For any two positive real numbers m, N, define an operation ⊙ m ⊙ n = m + n [M and N are the same parity], Mn [M and N are different parity], then M = {(a, b) ∣ a ⊙ B = 36, a, B

Enumeration. 36 = 1 + 35 = 3 + 33 = So 1, 3, 5 , 35 belong to m, 36 = 1 * 36 = 3 * 12 = 4 * 9, so 4,12,36 belong to m, probably