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How many days are there before November 12, 2010 and June 7, 2011
206 days. Today is the 13th. So it should be 205 days
How many days is today from June 10, 2006
393 days
Today is October 18, a few days before the Spring Festival in 2011
109
How is 9 8 7 6 5 4 3 2 1 equal to 1
(9-8) * (7-6) * (5-4) * (3-2) * 1 = 1
9-8+7-6-5+4-3+2+1=1
The idea is to make a 1 for every two numbers, and then the last 1 is 1
Calculated by 1.2.3.4.5.6.7.8.9.10, the final value is 5
You can't change the order of numbers. Each number can only be added, subtracted, multiplied and divided once
What if you have to use addition, subtraction, multiplication and division? Brackets cannot be used
1 - 2 + 3 * 4 * 5 / 6 + 7 + 8 - 9 - 10 = 5
1+2+3+4+5+6+7+8+9+10…… +How much is 100
5050
1-50 sheets 15 yuan 51-100 sheets 13 yuan 101 sheets above 10 yuan
A total of 105 students from three or four classes of grade seven in a school went to the park. Among them, the number of students from three classes was less than 50. After calculation, they found that if the two classes bought tickets for the unit, the total cost was 1463 yuan. How many students were there in each class? How much money could the two classes save if they bought tickets as a whole
There are x people in class 3 and 105-x people in class 4
Because x < 50, so 105-x > 50
If x > 5
15x + 13×(105-x) = 1463
If x = 49, then 105-x = 56
If x < 5
15x + 10×(105-x) =1463
The solution is x = 82.6 (rounding off)
1463 - 105×10 = 413
A: there are 49 people in class 3 and 56 people in class 4. If you buy tickets in two classes as a whole, you can save 413 yuan
Calculate this question (- 1) + 2 + (- 3) + 4 + ··· + 100 + (- 101)
=-1+50*（-1）
=-1+（-50）
=-51
1 / 1 * 2 + 1 / 2 * 3 + 1 / 3 * 4 +. 1 / 100 * 101 simple calculation process
1/(1×2)+1/(2×3)+1/(3×4)+.+1/(100×101)
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+…… +(1/100-1/101)
=1-1/2+1/2-1/3+1/3-1/4+…… +1/100-1/101
=1-1/101
=100/101
Among the natural numbers from 1 to 100, there are () even numbers that are multiples of 5 and () odd numbers that are multiples of 5
There are (20) even numbers that are multiples of 5 and (10) odd numbers that are multiples of 5
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