On the binary linear equations of X and Y [ax-2by = 1 bx-2ay2], the solution is [x = 1 y = 2], then a =? B =? Er, the title is wrong Yes: On the binary linear equations of X and Y [ax-2by = 1 bx-2ay = 2], the solution is [x = 1 y = 2], then a =? b=?

On the binary linear equations of X and Y [ax-2by = 1 bx-2ay2], the solution is [x = 1 y = 2], then a =? B =? Er, the title is wrong Yes: On the binary linear equations of X and Y [ax-2by = 1 bx-2ay = 2], the solution is [x = 1 y = 2], then a =? b=?


a-4b=1
b-4a=2
a=-0.6
b=-0.4



It is known that the solution of the system of equations ax + by = 5 CX + dy = - 3 is x = 2 y = 1. Xiaomingcuo regards B as 6, and the solution is x = 11 y = - 1 to find the values of a, B, C and D~


If you look at ACD = 6 correctly, you can see that ACD = 6 is correct
Then 11a-6 = 5, 11c-d = - 3
The solution is a = 1, but CD is not yet solved
Because when we don't misinterpret B as 6, the correct solution is x = 2, y = 1
Substituting in, we get 2A + B = 5,2c + D = - 3, because a = 1 is right. Substituting in, we get 2 + B = 5,2c + D = - 3
So the correct value of B is 3
Because 11c-d = - 3, 2C + D = - 3
So the solution is C = - 6 / 13, d = - 3
In conclusion, a = 1, B = 3, C = - 6 / 13, d = - 27 / 13



Given that the solution of AX + by = 2; CX dy = 5 is x = 2; y = - 1, then the solution of a (x-1) + B (y + 2); C (x-1) - D (y + 2) = 5 is


Given that the solution of the system ax + by = 2; CX dy = 5 is x = 2; y = - 1, so 2a-b = 2,2c + D = 5A (x-1) + B (y + 2) = ax + by-a + 2B, ax + by = 3 (a-b) C (x-1) - D (y + 2) = cx-dy-c-2d, CX dy = 3 (c + D), then the solution of the system a (x-1) + B (y + 2) = 2; C (x-1) - D (y + 2) = 5 is x = 3, y = - 3



How to calculate 180 (n-2) △ 2 = 3 (360 △ n) + 20?


(180n-360)/2=90n-180
720/3n+20=240n+30
240n-90n=-180-30
150n=-240
n=-1.6



Can s cone table = π R & # 178; × π (R & # 178; + H & # 178;) × n ° / 360
S cone table = π R & # 178; + π RL why is π RL? What does π RL mean


The formula you give can also be used. The general formula is: cone surface area = π R & # 178; + π RL π is the circumference; R: radius L: generatrix ~ moment forever 523 for you, I wish you progress in your study ~ ~ ~ ~ if you agree with my answer, Please click the [adopt as a satisfactory answer] button in time ~ ~ the mobile phone questioner can comment "satisfied" on the client ~ ~ ~ your adoption is my driving force ~ ~ ~ if there are any new questions, please ask me for help. The answer is not easy, please understand~~



Is n π R & # / 360 a monomial or a polynomial?


No addition or subtraction, monomial



Verify the external angle of the triangle and 360 degrees


Let the triangle be ABC
The outer angle of ∠ a = ∠ B + C
The outer angle of ∠ B = ∠ a + C
The outer angle of ∠ C = ∠ B + A
Add them up
2 ∠ a + 2 ∠ B + 2 ∠ C = sum of external angles of triangle ABC
2 (∠ a + B + C) = sum of exterior angles of triangle ABC
2 * 180 = sum of exterior angles of triangle ABC = 360 degrees



It is known that the sum of exterior angles of an n-polygon is 360 ° and proved that the sum of interior angles of an n-polygon is (n-2) × 180 °


The sum of each inner angle and its corresponding outer angle is 180 degrees
An n-polygon has n inner and outer angles
So their sum is 360n degrees
The sum of the outer angles is 360 degrees
So the sum of internal angles = 360n-360 = 180 * 2n-180 * 2 = 180 * (n-2) degrees



Calculation (n-2) * 180 + 360 / N = 600 should be based on the level of junior high school students


(N-2)*180+360/N=600
N cannot be 0
Multiply both sides of the equation by n
180n * (n-2) + 360 = 600N
That is 180n ^ 2-360n + 360 = 600N
Transfer the term, get 180n ^ 2-960n + 360 = 0
Divide both sides by 60 and you'll get 60
3N^2-16N+6=0
That is to say, the two roots of the quadratic equation AX ^ 2 + BX + C = 0 are
When B ^ 2-4ac > = 0
X = [- B ± (b ^ 2-4ac) ^ (1 / 2)] / 2A;
So n = [8 ± √ 26] / 3



(n-2) * 180 = 180n-360


Distribution law: (n-2) * 180 = 180 * n-2 * 180 = 180n-360 wish you a happy study and a higher level! If you have any questions, please feel free to ask! Please adopt them in time_ ∩)o