Given that the solution of the system {x + y = - 10, ax-2by = 32} is the same as that of the system {X-Y = - 6, 2aX + by = 44}, find the value of (3a-b) (2a + 5b)

Given that the solution of the system {x + y = - 10, ax-2by = 32} is the same as that of the system {X-Y = - 6, 2aX + by = 44}, find the value of (3a-b) (2a + 5b)

{x+y=-10;x-y=-6
X = - 8, y = - 2
Substituting x = - 8, y = - 2 into ax-2by = 32; 2aX + by = 44
So - 8A + 4B = 32, - 16a-2b = 44
4b-8a=32,16a+2b=-44
The solution is: B = 2, a = - 3
Substituting a = - 3, B = 2 into (3a-b) (2a + 5b)
(-9-2)(-6+10)=-11*4=-44

It is known that the solutions of the equations {ax + 2by = 4, x + y = 1 and {X-Y = 3, BX + (A-1) y = 3 about X ` y are the same, and the value of AB is obtained

The same solution of two equations
Then the solution satisfies x + y = 1, X-Y = 3
The solution of this system of equations is x = 2, y = - 1
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2a-2b=4,2b+(1-a)=3
The solution is a = 6, B = 4
So AB = 24

Given that a = 2x & # 178; 3ax-2x-1, B = - X & # 178; + AX-1, and the value of 3A + 6b is independent of X, the value of a can be obtained

If a = 2x (and if a = 2x-178; (3ax-2x-178; + 3ax-2x-2x-1, then the value of 3A + 6B = 3 (2x-178; (3ax-2x-178; + 3ax-2x-178; + 3ax-2x-178; + 3ax-2x-178; + 3ax-2x-3-6x-2x-1, then the value of 3A + 6B = 3A + 6B = 3 (2x-2x-178; (2x-178; + 3ax-2x-178; + 3ax-2x-2x-178; + 3ax-2x-178; + 3ax-6 = (15a-6 = 0A = 5A = 6A = 6 / 15 = 6 / 15 = 6 / 15 = 6 / 15 = 2 / 15 = 2 / 15 = 2 / 15 = 2 / 15 = 2 / 5 if if a = 2x178 = 2x-6-6 = 2x-178 = 6-178-6-it's not easy