(for a three digit number, the number on the hundreds is twice as big as the number on the tens, and the number on the one digit is twice as big as the number on the tens.) A three digit number in the hundreds is one times larger than the number in the tens, and the number in the one digit is one times smaller than the number in the tens. If the number in the hundred of the three digit number is exchanged with the number in the one digit number, then the three digit number is 99 times larger than the original three digit number, and the original three digit number can be obtained

(for a three digit number, the number on the hundreds is twice as big as the number on the tens, and the number on the one digit is twice as big as the number on the tens.) A three digit number in the hundreds is one times larger than the number in the tens, and the number in the one digit is one times smaller than the number in the tens. If the number in the hundred of the three digit number is exchanged with the number in the one digit number, then the three digit number is 99 times larger than the original three digit number, and the original three digit number can be obtained

Let ten be X
The prime bit is 3x-1
100 is 2x + 1
So it turns out to be 3x-1 + 100
The swap is 100 (3x-1) + 10x + (2x + 1)
So [100 (3x-1) + 10x + (2x + 1)] - [100 (2x + 1) + 10x + (3x-1)] = 99
312x-99-213x-99=99
99x=297
x=3
100(2x+1)+10x+(3x-1)=213x+99=738
A: the original number is 738

A two digit, ten digit to one digit ratio is 2:3
If the difference between the new two digits and the original two digits is 18, what is the original two digits

If 2x and 3x are set as follows:
10×3x+2x-10×2x-3x=18;
32x-23x=18;
9x=18;
x=2;
So the original two digit number is 46;
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The solution of the equation 5x-2a = 2x + 1 of X is the value of a for x = 2

The solution of the equation 5x-2a = 2x + 1 of X is x = 210-2a = 4 + 1 a = 5 / 2