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There are 341 pine trees in a primary school, which are divided into three grades. One fifth of the total in Grade 6 is equal to one fourth of that in Grade 5, and two thirds of that in grade 4 There are 341 pine trees in a primary school, which are divided into three grades. One fifth of the total in Grade 6 is equal to one fourth of the total in Grade 5 It's equal to 1 / 2 of the fourth grade. How many trees are there in each of the three grades?
341÷(5+4+2)=31
31÷1/5=155
31÷1/4=124
31÷1/2=62
A: 62 in the fourth grade, 124 in the fifth grade and 155 in the sixth grade
1×2×3×4······×48×49×50＝?
How many zeros are there at the end
The paper says it's not 10 zeros, it's 65 digits
The answer is that it's impossible for someone to ask you to work out the result
If you want to figure out how many zeros are at the end, you can figure them out
We can figure out how many factors are in this equation
There are 12 5 factors in 5 10 15 20 25 30 35 40 45 50
So there are 12 zeros at the bottom
1/2+（1/3+2/3）+（1/4+2/4+3/4).+(1/50+2/50.+48/50+49/50) .
There is also a + sub question a B C3 people go to the same direction to share the fare a get off at 1 / 3 B get off at 2 / 3 C get off the whole journey the fare is 54 yuan ask ABC how to distribute the fare is more reasonable ask ABC to write the formula
1/n+2/n+3/n+…… +(n-1)/n
=[1+2+…… +(n-1)]/n
=[n(n-1)/2]/n
=(n-1)/2
So the original formula = 1 / 2 + 2 / 2 + 3 / 2 + +49/2
=(1+2+…… +49)/2
=49*50/2/2
=612.5
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