On Inequality: find y = (√ x square + 2x + 2) + (√ x square - 4x + 8)_ Minimum value of

On Inequality: find y = (√ x square + 2x + 2) + (√ x square - 4x + 8)_ Minimum value of


Y = (√ (x + 1) ^ 2 + (0-1) ^ 2) + (√ (X-2) ^ 2 + (0-2) ^ 2)
It is equivalent to the sum of the distances from point (x, 0) to point a (- 1,1) and point B (2,2)
Find a about X-axis symmetric point A1 (- 1, - 1) A1B, length 3 √ 2 is the minimum value