Given that real numbers a and B satisfy a > b, prove: - A ^ 2-A < - B ^ 3-b

Given that real numbers a and B satisfy a > b, prove: - A ^ 2-A < - B ^ 3-b

A ^ 2 should be a ^ 3
prove:
Let f (x) = - x ^ 3-x
Derivation: F '(x) = - 3x ^ 2-1B
So: F (a)

Two points a (- 1,2), B (m, 3) are known, and the real number m belongs to [- √ 3 / 3, √ 3-1]
Find the range of inclination angle α of line ab

So when m = √ 3-1, Tan α = (3-2) / (√ 3-1 - (- 1)) = √ 3 / 3, so α = π / 6. When m = - √ 3 / 3, Tan α = (3-2) / (- √ 3 / 3 - (- 1)) = (3 + √ 3) / 2, so α = arctan (3 + √ 3) / 2. So α ∈ [π / 6, (3 + √ 3) / 2]

Two points a (- 1,2), B (m, 3) are known, and the real number m belongs to [- √ 3 / 3-1, √ 3-1]
Find the range of inclination angle α of line ab

k=1/(m+1)
-√3/3