Find LIM (x → 0) (x-sinx) / 2x ^ 3 =?

lim(x→0)（x-sinx）/2x^3
=lim(x→0)（1-cosx)/(6x^2)
=lim(x→0) sinx/(12x)
=lim(x→0) cosx/12
=1/12

The mathematician LIM (x tends to π / 2) {in (SiNx)} / (π - 2x) ^ 2. Is there a simple way

Law of lobida

Ask: LIM (x tends to 0) (Cotx - (e ^ 2x) / SiNx) the answer is - 2

lim(x→0)（cotx-(e^2x)/sinx)
=lim(x→0)[（cotxsinx-(e^2x)]/sinx
=lim(x→0)[（cosx-(e^2x)]/x (0/0)
=lim(x→0)[（sinx-2e^2x
=-2

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