求lim(x→0)(x-sinx)/2x^3=?

求lim(x→0)(x-sinx)/2x^3=?


lim(x→0)(x-sinx)/2x^3
=lim(x→0)(1-cosx)/(6x^2)
=lim(x→0)sinx/(12x)
=lim(x→0)cosx/12
=1/12



那位數學高手lim(x趨向於π/2){in(sinx)}/(π-2x)^2請問有沒有簡便的方法啊


洛必達法則



求:lim(x趨向於0)(cotx-(e^2x)/sinx)答案是-2


lim(x→0)(cotx-(e^2x)/sinx)
=lim(x→0)[(cotxsinx-(e^2x)]/sinx
=lim(x→0)[(cosx-(e^2x)]/x(0/0)
=lim(x→0)[(sinx-2e^2x
=-2