The seventh power of [(x + y) (X-Y)] and the fifth power of [(- X-Y) (X-Y)] is the square of - 2 (- XY), where x = - 2, y = - 1 is the process of solving the square difference formula,

The seventh power of [(x + y) (X-Y)] and the fifth power of [(- X-Y) (X-Y)] is the square of - 2 (- XY), where x = - 2, y = - 1 is the process of solving the square difference formula,

(x+y)(x-y)=x^2-y^2,
(-x-y)(x-y)=-(x+y)(x-y)=-(x^2-y^2),
The original formula = (x ^ 2-y ^ 2) ^ 7 ÷ [(x ^ 2-y ^ 2)] ^ 5-2x ^ 2Y ^ 2
=-(x^2-y^2)^2-2x^2y^2
When x = - 2, y = 1, the original formula = - (4-1) ^ 2-2 * 4 * 1 = - 9-8 = - 17

If n lines intersect at a point, is the logarithm of the adjacent complementary angle twice that of the vertex angle?

That's right
First look at two straight lines, two adjacent complementary angles and one opposite vertex angle
That is to say, in a point where n straight lines intersect, any angle formed by two straight lines has only two adjacent complementary angles and one opposite vertex angle
And the cumulative relationship is always double

If 2006 different lines intersect each other, then the logarithm of vertex angle can be formed?
A 2011015
B 4022030
C 8044060
D is not right

B because there are 1 + 2 + 3 +. + 2005 = 2011015 pairs of different intersecting lines when 2006 lines intersect, and a pair of intersecting lines has 2 pairs of vertex angles, so there are 2011015 * 2 = 4022030 pairs of vertex angles