Given that the sum of three consecutive odd numbers is 15 more than the sum of two even numbers between them, find three consecutive odd numbers

Given that the sum of three consecutive odd numbers is 15 more than the sum of two even numbers between them, find three consecutive odd numbers

Let these three odd numbers be (2n + 1), (2n + 3), (2n + 5)
According to the meaning of the title, there are (2n + 1) + (2n + 3) + (2n + 5) - (2n + 2) - (2n + 4) = 15
n=6
So these three consecutive odd numbers are 13 15 17

Given that the sum of three consecutive odd numbers is 15 more than the sum of two even numbers between them, find the three consecutive even numbers
And write down the calculation process?

Let three consecutive odd numbers be 2n-1,2n + 1,2n + 3
Then the two even numbers between phases are 2n, 2n + 2
（2n-1）+（2n+1）+（2n+3）＝2n+（2n+2）+15
Solution
n=7
These three consecutive odd numbers are 13, 15 and 17

If the sum of three consecutive even numbers is 2004, what is the difference between the largest one and the smallest one

No matter what the sum is, the difference between the maximum and minimum of three consecutive even numbers is always 2 + 2 = 4

If the sum of three consecutive even numbers is 2004, what is the even number in the middle

Let an even number in the middle be X
（X-2）+X+（X+2）=2004
X=668

If the sum of three consecutive even numbers is 2004, do you know what the smallest of the three numbers is?

In the middle: 2004 △ 3 = 668
So the smaller one is: 668-2 = 666

If the sum of four consecutive even numbers is 2004, then the largest number is______ ．

Let the four consecutive even numbers be: 2n, 2n + 2, 2n + 4, 2n + 6. According to the meaning of the question, we can get: 2n + (2n + 2) + (2n + 4) + (2n + 6) = 2004, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp

If the sum of four consecutive even numbers is 2004, then the largest number is______ ．

Let the four consecutive even numbers be: 2n, 2n + 2, 2n + 4, 2n + 6. According to the meaning of the question, we can get: 2n + (2n + 2) + (2n + 4) + (2n + 6) = 2004, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp

What is the rule that the sum of three consecutive even numbers = two consecutive odd numbers

Let m and n be even numbers 2n-2, 2n, 2n + 2, odd numbers 2m-1, 2m + 1, so 6N = 4m and 3N = 2m, n is a multiple of 2, M is a multiple of 3

Given that the sum of three consecutive numbers is 75, then it means the smallest of the three odd numbers
Hurry up~~~~~~~~

If the three numbers are 24, 25 and 26, the smallest odd number is 25

It is known that the sum of five consecutive odd numbers is 75, and the number in the middle is X

From the meaning of the title
These five numbers are x-4x-2x + 2x + 4
（x-4）＋（x-2）＋x＋（x＋2）＋（x＋4）=75
x-4＋x-2＋x＋x＋2＋x＋4=75
5x＋0=75
5x=75
x=15
So these numbers are 11 13 15 17 19