What is one plus two plus three plus four plus five all the way to 100 Add with the beginning and end
(1+100)×(100÷2)
=101×50
=5050
When calculating the value of 1 + 3 + 3's quadratic + ·· + 3's 100th power, let s = 1 + 3 + 3's quadratic + ·· + 3's 100th power, then 3S = 3 + 3's quadratic
The 101st power of the third power + ·· + 3 is 2,2-1, and the 101st power of 2S = 3 is - 1, so the 101st power of S = 3 / 2 is - 1. Try to use the above method to find the value of the quadratic power of 1 + 8 + 8 + ·· + 8 to the power of 2004, and find the value of the quadratic power of 1 + X + X + · + X to the power of n (x is not equal to 1)
Let s = 1 + 8 + 8 to the second power + ·· + 8 to the fourth power
Then 8s = quadratic power of 8 + 8 + 8 + ·· + 2004 power of 8 + 2005 power of 8
By subtracting the two formulas, we get: 8s-s = 8 to the power of 2005-1
S = 1 / 7 (power of 8-1)
Let s = 1 + X + X to the second power + ·· + X to the nth power
Then XS = quadratic power of X + X + ·· + n power of X + N + 1 power of X
By subtracting the two formulas, we get the following result:
(x-1) s = n + 1 power-1 of X
S = (n + 1 power of x-1) / (x-1)
1 / 3-1 / 3-1 / 3-1 / 3 of the square - 1 / 3 to the 100th power
The square of 1-1 / 3-1 / 3 is the third power of 1 / 3 - 1 / 3 to the power of 100;
1 / 3 + the square of 1 / 3 + the third power of 1 / 3 +1 / 3 to the 100th power = a;
3A = the square of 1 + 1 / 3 + 1 / 3 + the third power of 1 / 3 +1 / 3 to the power of 99;
2A = 100th power of 1-1 / 3;
The square of 1-1 / 3-1 / 3 is the third power of 1 / 3 - 1 / 3 to the 100th power
=1 - (100th power of 1-1 / 3) / 2
=(100th power of 1 + 1 / 3) / 2