Quarter and three eighths
Multiply the denominator by two to get two eighths. Add three eighths to get five eighths
How to do root 2004 times 2005 times 2006 times 2007 + 1?
Detailed explanation
Let a = 2005, B = 2006, first calculate the things in the root sign (A-1) AB (B + 1) + 1 and multiply them one by one to get AABB + (aab-abb) - AB + 1. Because a = B-1, the things in the root sign aab-abb equal to - AB become aabb-ab-ab + 1, that is, the factorization of AB * ab-2ab + 1 gets (AB-1) * (AB-1) squared, and the result is AB-1 2
1 by 1 / 2 + 2 by 1 / 3 + 3 by 1 / 4 +. 2004 by 1 / 2005 = how much?
Original formula = 1 / 2 + 1 / 3 - 1/2004 +1/2004 - 1/2005 = 1 - 1/2005 = 2004/2005