A. B and C are all non-zero natural numbers. The following can show that the formula of a > b is () A.A △ 1 B.A / C1

A. B and C are all non-zero natural numbers. The following can show that the formula of a > b is () A.A △ 1 B.A / C1

B
C of a

If the median of five non-zero natural numbers is 3 and the mode is 7 and unique, it is necessary to find the sum of five non-zero natural numbers

Mode is 7 and unique, that is to say, the two digits are 7 and 7
The results show that the arrangement of the five numbers is x, x, 3, 7 and 7
Moreover, the two XS cannot be less than 3 or 0, and they cannot be repeated, so the two XS are 1 and 2 respectively
Formula:
Suppose two unknown numbers, one is x, the other is x + 1
X+(X+1)=3
2X=3-1
X=2/2
X=1
1+1=2
So one number is 1 and one is 2

A non-zero natural number divided by 3,2,4,2,5,2 is the smallest——————
Solved + 10

Answer: 62
Because the remainder is 2, so as long as the least common multiple of 3,4,5 plus 2 is the smallest number
3. The least common multiple of 4 and 5 is 60, 60 + 2 = 62, so the minimum is 62