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There is an operation program, which can make a ⊕ B = n (n is a constant), get (a + 1) ⊕ B = n + 1, a ⊕ (B + 1) = n-2=______ ．
The rule is that the former increases by one, the result increases by one, the latter increases by one, and the result decreases by two, then 1 ⊕ 1 = 22008 ⊕ 2008 is 2 plus 2007 1 minus 2007 2, that is 2 + 2007 × 1-2007 × 2 = - 2005
There is an operation program, which can make a ⊕ B = n (n is a constant), get (a + 1) ⊕ B = n + 1, a ⊕ (B + 1) = n-2=______ ．
The rule is that the former increases by one, the result increases by one, the latter increases by one, and the result decreases by two, then 1 ⊕ 1 = 22008 ⊕ 2008 is 2 plus 2007 1 minus 2007 2, that is 2 + 2007 × 1-2007 × 2 = - 2005
There is an operation program, which can make a ⊕ B = n (n is a constant), get (a + 1) ⊕ B = n + 1, a ⊕ (B + 1) = n-2=______ ．
The rule is that the former increases by one, the result increases by one, the latter increases by one, and the result decreases by two, then 1 ⊕ 1 = 22008 ⊕ 2008 is 2 plus 2007 1 minus 2007 2, that is 2 + 2007 × 1-2007 × 2 = - 2005
RELATED INFORMATIONS
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- 14. The concept of natural number
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