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There is an operation program that can make (a + 1) ♁ B = n + 2, a ♁ (B + 1) = n-3, 1 ♁ 1 = 42009 ♁ 2009 =?
I've been thinking about this problem for a long time. Analysis: ∵ (a + 1) ⊙ B = n + 2. A ⊙ (B + 1) = n-3 ∵ (a + 1) ⊙ (B + 1) = (n + 2) - 3 = n-1 ① And a ⊙ B = n, that is, n = a ⊙ B is brought into the formula, that is, (a + 1) ⊙ (B + 1) = a ⊙ B-1, so: 2009 ⊙ 2009 = (2008 + 1) ⊙ (200
If M + 1 = n, (M and N are non-zero natural numbers), then the greatest common divisor of M and N is______ The least common multiple is______ ．
Because m + 1 = n, we know that m and N are two adjacent natural numbers, they are coprime numbers, so the greatest common divisor of M and N is 1, and the least common multiple is Mn
If M and N are known to be natural numbers, and N = m + 1, m and N are known to be natural numbers, and N = m + 1, then the greatest common factor () of M and N and the smallest common multiple ()
Because n = m + 1, m n is two continuous natural numbers
The greatest common factor of continuous natural number is 1, and the least common multiple is mxn
RELATED INFORMATIONS
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- 2. If the quotient of natural number a divided by natural number B is 9, then the greatest common factor of a and B is () reason
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- 11. There is an operation program, which can make a ⊕ B = n (n is a constant), get (a + 1) ⊕ B = n + 1, a ⊕ (B + 1) = n-2=______ ．
- 12. There is an operation program that can make (a + 1) ⊕ B = n + 1, a ⊕ B + 1 = n-2 when a ⊕ B = n (n is a constant). Now we know that 1 ⊕ 1 = 2, then 3 ⊕ 3=______ ．
- 13. There is an operation program, can make: a ⊕ B = n (n is a constant), get (a + 1) ⊕ B = n + 1, a ⊕ (B + 1) = n-2, now known, 1 ⊕ 1 = 2, then 2013 ⊕ 2013=______ ;2014⊕2014=________
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- 15. The concept of natural number
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