If x ^ 2 + ax-9 = (x + m) (x + n) m, n is a positive integer, then the value of natural number a is? A.0, - 8.8b. Plus or minus 8 c.0, - 8 d.0,8 d.0
x^2+ax-9=(x+m)(x+n)=x^2+(m+n)x-mn
be
m+n=a
mn=-9=(-1)x9=1x(-9)=(-3)x3
So: a = m + n = 8, - 8,0
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