Given that X and y are natural numbers and satisfy XY + X + y = 11, we can find the value of X and y

Given that X and y are natural numbers and satisfy XY + X + y = 11, we can find the value of X and y

xy+x+y+1=12
(x+1)(y+1)=12
So x + 1 = 1, y + 1 = 12 or x + 1 = 2, y + 1 = 6 or x + 1 = 3, y + 1 = 4 or x + 1 = 4, y + 1 = 3 or x + 1 = 6, y + 1 = 2 or x + 1 = 12, y + 1 = 1
So x = 0, y = 11 or x = 1, y = 5 or x = 2, y = 3 or x = 3, y = 2 or x = 5, y = 1 or x = 11, y = 0

(1) X, y satisfy the square of X + xy = 35 (2) x, y satisfy the square of X - the square of y = 45
The natural numbers x and y are obtained according to the given conditions

(1)x^2+xy=35
x(x+y)=35
x

72 △ X & sup2; = y & sup2; XY is a natural number, and the minimum x is () a: 2 B: 3 C: 4 D: 5
72 △ X & # 178; = y & # 179; XY is a natural number, and the minimum x is ()
A:2 B:3 C:4 D:5
It's y-179; it's not y-178;

a:2