The result of (X & sup3; + MX + n) × (X & sup2; - 5x + 3) does not contain the terms of X & sup3; and X & sup2; to find the value of M, n

The result of (X & sup3; + MX + n) × (X & sup2; - 5x + 3) does not contain the terms of X & sup3; and X & sup2; to find the value of M, n

The following results are obtained: (supx; + 3 M + supx; + 3 M + ∧ - supx; + 3 M + ∧ (supx; + 5 m) = ∧ (supx; + 3 m) ∧ (supx; + 3 m) ∧ + 3 M + ∧ (supx; + 3 M) ∧ (supx; + 3 M + X; + 3 M + 3 M + 3 M + X; + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 m + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3 M + 3

In the equation y = ax & sup2 + BX + C, when x = 1, y = - 2; when x = - 1, y = 20; when x = 3 / 2 and x = 1 / 3, the values of Y are equal, and the values of a, B and C are obtained

Substituting x = 1, y = - 2 = > A + B + C = - 2
Substituting x = - 1, y = 20 = > A-B + C = 20
=>b=-11
X = 3 / 2, x = 1 / 3, y are equal, indicating that the position of symmetry axis = > - B / 2A = (3 / 2 + 1 / 3) / 2 = 11 / 12 = > 6B + 11a = 0
=>a=6
Substitute a + B + C = - 2 to get
c=3

Given the equation 1993x + 4Y = 6063, where x and y are natural numbers, find the value of XY

4Y is even
So x is odd
Y is not an integer when x = 1
So x = 3
4y=6063-1993x3=84
y=21
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