As shown in the figure, if the inner angles of the Pentagon ABCDE are equal, and ∠ 1 = 2, ∠ 3 = 4, then X=______ ．

As shown in the figure, if the inner angles of the Pentagon ABCDE are equal, and ∠ 1 = 2, ∠ 3 = 4, then X=______ ．

The sum of internal angles of Pentagon ABCDE = (5-2) × 180 ° = 540 °, while the internal angles of Pentagon ABCDE are equal, ∧ e = ∠ EDC = ∠ C = 540 ° 5 = 108 °, ∧ 1 + 2 + e = 180 °, ∧ 3 + 4 + C = 180 ° and ∧ 1 = 2, ∧ 3 = 4, ∧ 1 + 3 = 180 ° - 108 ° = 72 °, ∧ x = EDC -

As shown in the figure, △ ABC is an equilateral triangle with side length of 6, P is a moving point on AC side, moving from a to C (not coincident with a and C), q is a point on CB extension line, moving from B to CB extension line at the same speed as point P (not coincident with B), PE ⊥ AB through p to e, connecting PQ to AB to d (1) When ∠ BQD = 30 °, find the length of AP; (2) whether the length of line ed changes in the process of motion? If it does not change, find out the length of line ed; if it changes, explain the reason

(1) Let AP = x, then PC = 6-x, QB = x, QC = QB + BC = 6 + X, in RT △ QCP, BQD = 30 ° and PC = 12qc, i.e. 6-x = 12 (6 + x), the solution is x = 2, AP = 2

As shown in the figure, in the regular pentagon ABCDE, every inner angle is equal. If angle 1 is equal to angle 2, is angle 3 equal

Equal

As shown in Figure 8, the inner angles of the Pentagon ABCDE are equal, and

Because the inner angles of the Pentagon are equal, each angle is 108 degrees
So angle 1 = angle 2 = 36 degrees angle 3 = angle 4 = 36 degrees
So angle ADB = angle EDC - angle EDA - angle BDC = 108-36-36 = 36 degrees

There is a five pointed star ABCDE, can you explain ∠ a + ∠ B + ∠ C + ∠ D + ∠ e = 180 degrees? If point B moves down to AC or other side of AC, is the above conclusion still exaggerated? Please explain the reason

Because the sum of the inner angles of the triangles is 180 degree, ∠ a + ∈ B + ∈ C +} D +} e = 180. It still holds. ∠ a + ∈ d = their outer angle ∠ e +} C = their outer angle. In this way, ∠ B and the two outer angles will be

A five pointed star is called ABCDE. How much is angle a plus angle B plus angle C plus angle D plus angle e

180 degrees

As shown in the figure, the sum of the five internal angles of the pentagram ABCDE is ∠ a + ∠ B + ∠ C + ∠ D + ∠ E=______ Degree

As shown in the figure, ∵ 1 = ∵ a + ∵ C, ∵ 2 = ∵ B + ∵ D, ∵ 1 + ∵ C + ∵ B + ∵ D, ∵ 1 + ∵ 2 + ∵ e = 180 °,