① 3 is the square root of, and the arithmetic square root of is. 2 if, then; if, then. 3 is known: in the formula, then. 4 when x, then
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If x ^ 2-3x + Q can be factorized in the range of integers, then the value of integer P can be______ .
-4
Factorization: (1) 2a3b2 (a-2b) 2-4a2b3 (2b-a) 2; (2) m3-6m2 + 9m
(1)2a3b2(a-2b)2-4a2b3(2b-a)2=2a2b2(a-2b)2(a-2b)=2a2b2(a-2b)3;(2)m3-6m2+9m=m(m2-6m+9)=m(m-3)2.
Decomposition factor M & # 178; + 6m + 8
With the method of matching,
m²+6m+8
=m²+6m+9-1
=(m+3)²-1
=(m+3+1)(m+3-1)
=(m+4)(m+2)
How to decompose factor 6m × m-m-12
=(2m-3)(3m+4)
Factorization: m ^ 2-10mn + 25N ^ 2 + 6m-30n + 8
m^2-10mn+25n^2+6m-30n+8
=(m-5n)^2+6(m-5n)+8
=(m-5n+2)(m-5n+4)
Factorization of 12x ^ 3 + 16x ^ 2-5x-3
Original formula = 12x ^ 3 + 4x ^ 2 + (12x ^ 2-5x-3)
=4X ^ 2 (3x + 1) + (4x-3) (3x + 1) (cross multiplication)
=(3x+1)(4x²+4x-3)
=(3x+1)(2x-1)(2x+3)
Factorization 5x ^ m + 1-10x ^ m + 5x ^ M-1
5x^m+1-10x^m+5x^m-1
=5x^(m-1)(x²-2x+1)
=5x^(m-1)(x-1)²
How to factorize 5x ^ 2 + (4m + 2) x + 2m-1 = 0?
Can this formula be factorized?
5X^2+(4M+2)X+2M-1=0
=(5x+1)(x+2m-1)
Because (5x + 1) (x + 2m-1)
=5X^2+(4M+2)X+2M-1=0
Factorization (m ^ 2-6) ^ 2-6 (m ^ 2-6) + 9=
(m^2-6)^2-6(m^2-6)+9
=(m^2-6-3)^2
=(m^2-9)^2
=(m+3)^2(m-3)^2