Factorization of 2A ^ 3b-3a ^ 3B + 3B ^ 3-2ab ^ 3

Factorization of 2A ^ 3b-3a ^ 3B + 3B ^ 3-2ab ^ 3


2a^3b-3a^3b+3b^3-2ab^3=-a^3b+3b^3-2ab^3=-b(a^3-3b^2+2ab^2)
Maybe the title is wrong



Factorization factor 4 (a-b) ^ 2-9a + 9b


4(a-b)^2-9a+9b
=4(a-b)^2-9(a-b)
=(a-b)(4a-4b-9)



Square of 9A - square of 4 (B + C) = factorization
The square of 9A - the square of 4 (B + C)=
Factorization


9a-4b-8bc-4c



The square of X + AX = BX (a, B are known numbers)


x²+ax-bx=0
x²+(a-b)x=0
x(x+a-b)=0
x=0 x=b-a



Decompose the square of factor 9a-6ac + the square of factor c-4b the square of factor A to the fourth power of factor B-the square of factor 1A + the square of factor 1b


The original formula = (3a-c) ² - 4B & #178; = (3a-c + 2b) (3a-c-2b)
The original formula = (A & # 178; B-1 / 4b) &# 178;



(factorization) the third power of 39 * 19-13 * 3, 9a square-4b square, 9t square-6t + 1


Original formula = 13 * 3 * 19-13 * 3 * 3 & # 178;
=13*3*(19-3²)
=39*10
=390
Original formula = (3a + 2b) (3a-2b)
The original formula = (3t-1) &# 178;



It is proved that 81a4 + 4b4 = (9a & # 178; + 6ab + 2B & # 178;) (9a & # 178; - 6ab + 2B & # 178;)


Left = 81a ^ 4 + 36a & # 178; B & # 178; + 4B ^ 4-36A & # 178; B & # 178;
=(9a²+2b²)²-(6ab)²
=(9a & # 178; + 6ab + 2B & # 178;) (9a & # 178; - 6ab + 2B & # 178;) = right



Decomposition factor A & # 178; B (a-b) - 6ab (B-A)


a²b﹙a-b﹚-6ab﹙b-a﹚
=a²b﹙a-b﹚+6ab﹙a-b﹚
=ab﹙a-b﹚﹙a+6﹚.



9A & # 178; b-6ab & # 178; + B & # 178;, 6x & # 178; - 12xy + 6y & # 178; 4x & # 178; Y-Y & # 179; factorization factor,


(1)9a^2b-6ab^2      =3ab(3a-2b)(2)6x^2-12xy+6y^2   =6(x^2-2xy+y^2)   =6(x-y)^2(3)4x^2y-y^3=-y(-4xy+y^2)



Factorization: ① 4x ^ 2-y ^ 2-4x-2y ② a ^ 2-1 / 4B ^ 2 + B-1
Factorization: ① 4x ^ 2-y ^ 2-4x-2y
②a^2-1/4b^2+b-1
If x ^ 2 + 1 / x ^ 2 = 6, then the value of X + 1 / X is ()
A. 2 b. - 2 C. ± 2 d. none of the above is true


① 4X ^ 2-y ^ 2-4x-2y = (2x + y) (2x-y) - 2 (2x + y) = (2x + y) (2x-y-2) ② a ^ 2-1 / 4B ^ 2 + B-1 = A & # 178; - (1 / 4) (B & # 178; - 4B + 4) = a & # 178; - (b-2) / 2 & # 178; = (a + (b-2) / 2) (a - (b-2) / 2) = (a + 0.5b-1) (a-0.5b + 1) x ^ 2 + 1 / x ^ 2 = 6, then the value of X + 1 / X is (d) A.2