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To prepare 200 grams of 20% dilute sulfuric acid with 98% concentrated sulfuric acid (density 1.84 g / cm3), how many ml of concentrated sulfuric acid and water are needed Company
If the volume of concentrated sulfuric acid and water is x and Y respectively, then
1.84g/cm3*X+1.0g/cm3*Y=200g
1.84g/cm3*X*98%=200g*20%
The solution is x = 22ml
Y=160ml
98% sulfuric acid with density of 1.84g/cm3 and 100g dilute sulfuric acid with solute content of 19.6%, how many grams of concentrated sulfuric acid are needed?
98%m = 19.6% * 100
If the problem is volume, then 1.84 * 98% v = 19.6% * 100
To prepare 250 ml of 1 mol / L sulfuric acid solution, the volume of concentrated sulfuric acid with 98% mass fraction of solute and 1.84 g / cm3 density is required
(1) The amount of sulfuric acid in 250ml 1mol / L sulfuric acid solution is: 0.25 * 1 * 98 = 24.5 (g)
(2) The volume of concentrated sulfuric acid with mass fraction of 98% and density of 1.84 g / cm3: 24.5 / (1.84 * 98%) = 13.6 (ML)
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