The mass of a hollow aluminum ball is 27g. After the hollow part is filled with alcohol, the total mass is 43g? (ρ aluminum = 2.7 × 103 kg / m3, ρ alcohol = 0.8 × 103 kg / m3)

The mass of a hollow aluminum ball is 27g. After the hollow part is filled with alcohol, the total mass is 43g? (ρ aluminum = 2.7 × 103 kg / m3, ρ alcohol = 0.8 × 103 kg / m3)

Mass of alcohol: m alcohol = m total - m ball = 43g-27g = 16g volume of alcohol: V alcohol = m alcohol ρ alcohol = 16g0.8g/cm3 = 20cm3 volume of aluminum block: V aluminum block = m aluminum block ρ aluminum block = 27g2.7g/cm3 = 10cm3 volume of aluminum ball: V ball = V alcohol + V aluminum block = 20cm3 + 10cm3 = 30cm3 answer: volume of aluminum ball is 30cm3

What is the volume of the 270 g aluminum ball suspended in water? What is the volume of the hollow part in the middle of the ball?

Suspension and water, the same density as water, 1 g / cm3
So the volume is 270 cubic centimeters
The density of aluminum is 2.7 g / cm3
So the volume of aluminum is 100 cubic centimeters
So the hollow is 170 cubic centimeters

The volume of the aluminum ball is 400cm3 power and the mass is 810g. Q: is the ball hollow or solid? If it is hollow, what is the volume of the hollow part?
Hurry, hurry! Hurry up-_-
Three solutions

The specific volume is 810g / 2.7g cubic centimeter = 300 cubic centimeter, so the hollow volume is 100 cubic centimeter
Specific mass
The specific density is slightly higher