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The mass of a 50cm 3 aluminum ball is 54G. Is the aluminum ball hollow or solid? If it is hollow, how large is the volume of the hollow part? The mass of a 50cm ^ 3 aluminum ball is 54G. Is the aluminum ball hollow or solid? If it is hollow, what is the volume of the hollow part? If it is filled with water, how much water can it hold? (p aluminum = 2.7 × 10 cubic kg | m3) I'm so anxious! How can the devil hurt me so much! So slow. I'm so angry-
solution
From ρ = m / v m al = 54G ρ al = 2.7 g / cm ^ 3
Then V al = m Al / ρ al = =20cm^3
Because V aluminum = 20cm ^ 3 ＜ V ball = 50cm ^ 3, the aluminum ball is hollow
Then V air = V ball - V aluminum = =30cm^3
Because V water = V air ρ water = 1g / cm ^ 3
So m water = ρ water V water = =30g
Answer: Yes .
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For reference only
The mass of a 50cm3 aluminum ball is 54G. Is it hollow or solid? If it is hollow, what is the volume of the hollow part?
From ρ = MV, if the aluminum ball is solid, its volume should be: V aluminum = m ρ = 54g2.7g/cm3 = 20cm3. Because V ball is larger than V iron, the ball is hollow. V air = V ball-v iron = 50cm3-20cm3 = 30cm3. A: the ball is hollow; the volume of the hollow part is 30cm3
The mass of an aluminum ball is 54G and the volume is 24cm3. Is it hollow or solid? (ρ aluminum = 2.7 × 103kg / m3)
What is the volume of the hollow part
The mass of an aluminum ball is 54G and the volume is 24cm3,
Then its density ρ = m / v = 54 * 10 ^ - 3kg / 24 * 10 ^ - 6m ^ 3 = 2.25 * 10 ^ 3kg / m ^ 3
Less than the density of aluminum 2.7 * 10 ^ 3kgkg / m ^ 3
So it's hollow
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