An aluminum ball has a mass of 810g and a volume of 400cm ^ 3. Is it hollow? (p aluminum = 2.7 * 10 ^ 3kg / m ^ 3) (please answer in three ways)

An aluminum ball has a mass of 810g and a volume of 400cm ^ 3. Is it hollow? (p aluminum = 2.7 * 10 ^ 3kg / m ^ 3) (please answer in three ways)

1. 2. The mass of 400 cm ^ 3 aluminum should be m = ρ v = 2.7 * 10 ^ 3 * 0.4 * 10 ^ - 3 = 1.08 kg = 1080 g, which is larger than the mass of the ball. 3. The volume of 810 g aluminum ball should be

The volume of the shot is 400cm and the mass is 810g. Q: if the hollow part is filled with water, what is the mass of the shot

V Pb = m Pb / ρ Pb = 810g / (11.3g / cm3) = 71.7cm3
V water = V-V lead = 328.3cm3
M water = ρ water V water = 1g / cm3 * 328.3cm3 = 328.3g
M = m lead + m water = 1138.3g

The mass of a hollow aluminum ball is 27g. After the hollow part is filled with alcohol, the total mass is 43g?
The density of aluminum is 2.7 × 10 ^ 3kg / m ^ 3, and that of alcohol is 0.8 × 10 ^ 3kg / m ^ 3

27g divided by the density of aluminum to get the volume V1 (which is the volume of aluminum in the aluminum ball)
43g minus 27g to get 16g, 16g divided by the density of alcohol to get the volume V2 (is the hollow volume in the aluminum ball)
V1 + V2 is the volume of the whole aluminum ball