The aluminum ball with a weight of 19.6n is slowly immersed in a container full of water, and 9.8N of water overflows from the container. The buoyancy of the aluminum ball is (, from which we can judge whether the aluminum ball is () hollow or solid? Why? It's better to be more detailed, especially the last question,

The aluminum ball with a weight of 19.6n is slowly immersed in a container full of water, and 9.8N of water overflows from the container. The buoyancy of the aluminum ball is (, from which we can judge whether the aluminum ball is () hollow or solid? Why? It's better to be more detailed, especially the last question,

1 19.6N-9.8N=9.8N
2 let the volume of the shot be XM & # 179;
Because the weight of the object = Volume X density
So 19.6 = 2.7 × 10 ^ 4x
The solution is: x = 49 / 67500
And because ρ water = 1.0 × 10 & # 179; kg / M & # 179;
So the quality of the boiled water is 7.26n
And because the actual mass of boiled water is 9.8N, that is, the volume of boiled water is equal to 49 / 50000m and larger than 49 / 67500m;
So the actual volume of the shot is larger than the theoretical volume,
So the shot is hollow

As shown in the figure, a small ball with a weight of 0.2N is pulled by the line and immersed in the liquid. If its buoyancy is 1.8n, then the line pull on the ball is ()
A. 1.8NB. 1.6NC. 0.2ND. 0N

∵ the buoyancy of the ball is equal to the gravity of the ball plus the pull of the line, that is: F float = G + F pull, ∵ f pull = f float - g = 1.8n-0.2n = 1.6n

If the buoyancy of a piece of iron immersed in water is 10N, and the buoyancy of an iron immersed in liquid is 8N, the density of the liquid will increase
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