What is the buoyancy of 2.34 kg steel immersed in water? (steel density 7.8 × 10 kg / M)

What is the buoyancy of 2.34 kg steel immersed in water? (steel density 7.8 × 10 kg / M)


Take g = 9.8 = ρ water GV row = 1.0 × 10x9.8x2.34 / 7.8 × 10 = 2.94 n



Rectangular aluminum block with density of 2.7 × 103 kg / m3 and volume of 5 cubic decimeters Second grade buoyancy calculation
A rectangular aluminum block with density of 2.7 × 103kg / m3 and volume of 5 cubic decimeters, when it is immersed in water, the pressure of water on its upper surface is 240n, and the pressure of water on its lower surface is 289n. At this time, how much buoyancy does the aluminum block suffer? What is the indication of the spring scale?


F floating = f up-f down = 289-240 = 49n
F pull + F float = g object
Fra = 2.7 * 5 * 9.8-49 (2.7 * 10 ^ 3kg / m ^ 3 = 2.7kg / DM ^ 3)
=83.3N



The buoyancy of a wood block with a mass of 1kg and a density of 0.4 × 10 ^ 3kg / m ^ 3 when it is still in water is 0


The wood is still in the water and buoyancy is equal to gravity
G=mg=1kg.9.8N/kg=9.8N
A: buoyancy is 9.8N