The mass of a hollow aluminum ball is 27g. After the hollow part is filled with alcohol, its total mass is 51g. The volume of the aluminum ball is calculated. (the density of the aluminum ball is 2.7 × 103kg / m3, and the density of the alcohol is 0.8 × 103kg / m3)

∵ρ = MV, ∵ ρ = MV, ∵ the volume of aluminum with the same mass as aluminum ball: V aluminum = m aluminum ball ρ aluminum = 27g2.7g/cm3 = 10cm3, the mass of alcohol: m alcohol = m total - M aluminum ball = 51g-27g = 24g, ∵ ρ = MV,

RELATED INFORMATIONS

1. The mass of a 50cm 3 aluminum ball is 54G. Is the aluminum ball hollow or solid? If it is hollow, how large is the volume of the hollow part? The mass of a 50cm ^ 3 aluminum ball is 54G. Is the aluminum ball hollow or solid? If it is hollow, what is the volume of the hollow part? If it is filled with water, how much water can it hold? (p aluminum = 2.7 × 10 cubic kg | m3) I'm so anxious! How can the devil hurt me so much! So slow. I'm so angry-
2. A 54G aluminum ball has a volume of 30cm3. Is the aluminum ball solid? If it is hollow, what is the volume of the hollow part?
3. For a 100 cubic centimeter aluminum block (ρ = 2.7 × 10 cubic kilogram per cubic meter), half of it is immersed in water. What is the buoyancy it receives What is wrong with multiplying the density of aluminum block by G and then multiplying the volume of aluminum block
4. A piece of aluminum, the volume is 0.05 cubic meters, immersed in alcohol by buoyancy is
5. The aluminum ball with a weight of 19.6n is slowly immersed in a container full of water, and 9.8N of water overflows from the container. The buoyancy of the aluminum ball is (, from which we can judge whether the aluminum ball is () hollow or solid? Why? It's better to be more detailed, especially the last question,
6. 3. The aluminum ball with a mass of 270 G is completely immersed in water, and the buoyancy of the ball is calculated? (ρ aluminum = 2.7 × 103 kg / m, 3 g = 10 N / kg) 3. The aluminum ball with a mass of 270 G is completely immersed in water, and the buoyancy of the ball should be calculated? (ρ aluminum = 2.7 × 103 kg / m, 3 g = 10 N / kg) (8 points) 3. The aluminum ball with a mass of 270g is completely immersed in water. How much buoyancy should the ball bear? (ρ al = 2.7 × 10 cubic kg / M 3 g = 10 N / kg) (8 points)
7. What is the buoyancy of 2.34 kg steel immersed in water? (steel density 7.8 × 10 kg / M)
8. When a solid aluminum ball with a mass of 2.7kg is put into mercury and water respectively, what is the buoyancy of the aluminum ball? (g = 10N / kg)
9. What is the buoyancy of a cubic kilogram of wood with a mass of 1kg and a density of 0.4 * 10 I first calculate the volume of the block, and then f = ρ, GV = 24.5n. Why is it wrong?
10. A piece of wood with a mass of 10kg and a density of 0.6x10 cubic kilogram per cubic meter is put into the water and the buoyancy is How many cows
11. An aluminum ball has a mass of 810g and a volume of 400cm ^ 3. Is it hollow? (p aluminum = 2.7 * 10 ^ 3kg / m ^ 3) (please answer in three ways)
12. The volume of aluminum is 400cm3 and the mass is 810g. Is the ball hollow or solid? What is the volume of Wilbur hollow? I know. Let's talk
13. The mass of a hollow aluminum ball is 27g. After the hollow part is filled with alcohol, the total mass is 43g? (ρ aluminum = 2.7 × 103 kg / m3, ρ alcohol = 0.8 × 103 kg / m3)
14. A hollow aluminum ball with a mass of 270g Put into the water suspension, find: 1, aluminum ball received buoyancy 2. The total volume of hollow aluminum spheres 3. The volume of the solid part of the aluminum ball What is the buoyancy of putting a solid aluminum block with a volume of 0.02m3 into mercury Ask less
15. Lithium is stored in paraffin. Is paraffin liquid or solid? What is the density of paraffin
16. The density of paraffin, ice and vegetable oil ranges from 0.09 g / cm3 to 0.92 g / cm3?
17. The density of salt water is 1.1g/cm3. In order to test whether the prepared salt water meets the requirements, 500ml salt water sample is taken, and its mass is 0.6kg. Please analyze whether such salt water meets the requirements. If not, how much salt or water should be added per 500ml of the original salt water?
18. Salt water seed selection is a kind of seed selection method invented by the working people in China. At present, salt water with density of 1.1 × 10 ~ 3 kg / M ~ 3 is needed. If the quality of 0.6 DM3 salt water is 540 G (1) Please calculate whether the brine meets the requirements? (2) If not, should salt or water be added? How many kg?
19. In salt water selection, salt water with density of 1.1x10 ^ 3kg / m ^ 3 is needed In the selection of salt water, salt water with a density of 1.1x10 ^ 3kg / m ^ 3 is needed. A student prepared 350ml salt water, and the quality of the salt water is 0.6kg. Ask whether the salt water meets the requirements? If not, how much water or salt should be added? Especially the process of how much to add!
20. Dilute 98% (density 1.84 g / cm3) concentrated sulfuric acid to 4 mol / L dilute sulfuric acid 250 ml, how many ml of concentrated sulfuric acid are taken