3. The aluminum ball with a mass of 270 G is completely immersed in water, and the buoyancy of the ball is calculated? (ρ aluminum = 2.7 × 103 kg / m, 3 g = 10 N / kg) 3. The aluminum ball with a mass of 270 G is completely immersed in water, and the buoyancy of the ball should be calculated? (ρ aluminum = 2.7 × 103 kg / m, 3 g = 10 N / kg) (8 points) 3. The aluminum ball with a mass of 270g is completely immersed in water. How much buoyancy should the ball bear? (ρ al = 2.7 × 10 cubic kg / M 3 g = 10 N / kg) (8 points)

3. The aluminum ball with a mass of 270 G is completely immersed in water, and the buoyancy of the ball is calculated? (ρ aluminum = 2.7 × 103 kg / m, 3 g = 10 N / kg) 3. The aluminum ball with a mass of 270 G is completely immersed in water, and the buoyancy of the ball should be calculated? (ρ aluminum = 2.7 × 103 kg / m, 3 g = 10 N / kg) (8 points) 3. The aluminum ball with a mass of 270g is completely immersed in water. How much buoyancy should the ball bear? (ρ al = 2.7 × 10 cubic kg / M 3 g = 10 N / kg) (8 points)

V row = V aluminum = m / ρ = 0.27kg/2.7 * 103kg / m3 = 0.0001m3
F floating = ρ liquid GV discharge = 1.0 * 103kg / m3 * 10N / kg * 0.0001m3 = 1n