A piece of aluminum, the volume is 0.05 cubic meters, immersed in alcohol by buoyancy is

A piece of aluminum, the volume is 0.05 cubic meters, immersed in alcohol by buoyancy is

It is known that V aluminum = 0.05m3, ρ alcohol = 800kg / m3, g = 10N / kg
Find: F =?
∵ the aluminum block is immersed in alcohol
Ψ V row = V aluminum = 0.05m3
∵ f = g row
=ρ liquid GV discharge
F = ρ GV row
=800kg/m3×10N/kg×0.05m3
=400N
Answer: the buoyancy of aluminum block is 400N

Is there a difference between the density of a liquid and the buoyancy of a liquid?
It's all down

The density of an object in a liquid is not only related to the density of the liquid, but also to the volume of the object immersed in the liquid. When the density of the object is less than the density of the liquid, the buoyancy of the object is the gravity of the object itself. When the density of the object is greater than that of water and alcohol, the buoyancy is greater in water

The aluminum ball with a weight of 19.6n is slowly immersed in a container full of water, and 9.8N of water overflows from the container. How much buoyancy does the aluminum ball suffer
The 19.6n aluminum ball was slowly immersed in a container full of water, and 9.8N water overflowed from the container,
(1) How buoyant is the aluminum ball?
(2) If the aluminum ball is placed in mercury, how much buoyancy is exerted on the aluminum ball when it is still? (it is known that ρ aluminum < ρ mercury g = 9.8n/kg)
Answer (1) 9.8N ask (2)

(1) According to Archimedes' principle, the buoyancy of physics is equal to the gravity of draining water. The overflow water in the container full of water is 9.8N, and the gravity of draining water is 9.8N, so the buoyancy is 9.8N
(2) The density of aluminum is smaller than that of mercury, so aluminum can float in mercury with buoyancy equal to its own gravity, that is, 19.6n