A copper aluminum alloy ball with a mass of 232g contains 54G aluminum. The density of copper is ρ copper = 8.9g/cm3, and the density of aluminum is ρ aluminum = 2.7g/cm3

A copper aluminum alloy ball with a mass of 232g contains 54G aluminum. The density of copper is ρ copper = 8.9g/cm3, and the density of aluminum is ρ aluminum = 2.7g/cm3

The mass of copper is m Cu = m total - M al = 232g-54g = 178g, the volume of copper is v Cu = m Cu ρ Cu = 178g8.9g/cm3 = 20cm3, the volume of aluminum is v al = m al ρ al = 54g2.7g/cm3 = 20cm3, so the volume of copper aluminum alloy ball is v = v Al + V Cu = 20cm3 + 20cm3 = 40cm3, the density of alloy ball is ρ = m total v = 232g40cm3 = 5

The ratio of silver to copper in a piece of aluminum alloy is 2:3, adding 6 grams of the same, a total of 36 grams is obtained

It shows that the original alloy is 30g silver copper ratio of 2:3, so the mass of original gold and silver is 12g copper is 18G, and the mass of copper in the new alloy is 24g
The ratio of silver to copper is 12:24 = 1:2
In addition, I feel that the problem is not ah, how to appear aluminum alloy?

A copper aluminum alloy block with a mass of 232g, containing 54G of aluminum

Aluminum volume: 54 / 2.7 = 20cm3
Copper mass: 232-54 = 178g
Copper volume: 178 / 8.9 = 20cm3
Total volume: 20 + 20 = 40cm3
Alloy density: 232 / 40 = 5.8g/cm3